Question

The angle of minimum deviation measured with a prism is ${30}^o$ and the angle of prism ${60}^o$. The refractive index of prism material is -

• A. $\sqrt{2}$
• B. $2$
• C. $\frac{3}{2}$
• D. $\frac{4}{3}$

Answer 1

The correct option is A $\sqrt{2}$

As we know,

$\mu =\frac{\sin \left(\frac{A+{\delta }_m}{2}\right)}{\sin \left(A/2\right)}=\frac{\sin {45}^o}{\sin {30}^o}=\sqrt{2}$