Question

The angle of prism is $60$ and its refractive index for green light is $\mathrm{1.5.}$ If a green ray passes through it, the deviation will be:

Answer 1

$\mu =\frac{sin\left(\frac{A+g_m}{2}\right)}{sin\frac{A}{2}}$

$1.5=\frac{sin\left(\frac{6+g_m}{2}\right)}{sin\frac{6}{2}}$

$1.5\times sin\frac{6}{2}=\frac{sin\left(\frac{6+g_m}{2}\right)}{sin\frac{6}{2}}$

$1.5\times 0.05=\frac{sin\left(\frac{6+g_m}{2}\right)}{sin\frac{6}{2}}$

${sin}^{-1}0.075=\frac{sin\left(\frac{6+g_m}{2}\right)}{}$

$\left(\frac{6+g_m}{2}\right)=4.3$

$6+g_m=8.6$

$g_m=2.6^0$