Question

The angle strain in cyclohexane is:

• A. $9$${}^o$ ${44}^{\prime }$
• B. $0$${}^o$ ${44}^{\prime }$
• C. $-5$ ${}^o$ ${16}^{\prime }$
• D. $5$ ${}^o$ ${16}^{\prime }$

Answer 1

Answer: (C)

$-5$ ${}^o$ ${16}^{\prime }$

The angle strain in cyclohexane is $d=\frac{{109}^0{28}^{\prime }-{120}^0}{2}=-5$ ${}^o$ ${16}^{\prime }$.
The negative value indicates that the bond angle $\left({120}^0\right)$ is greater than the tetrahedral bond angle $\left({109}^0{28}^{\prime }\right)$.