The angle subtended by a diameter at any point on the circumference of the circle is
A
90∘
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B
180∘
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C
45∘
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D
60∘
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Solution
The correct option is A90∘ Arc AB makes 180∘ at the center O of the circle where AB is the diameter of the circle.
i.e. ∠AOB=180∘
So, the angle subtended by the arc AB where AB is the diameter, at any point of the cricumeference of the circle will be half of ∠AOB
i.e. ∠APB=∠AOB2 =180∘2 =90∘