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Question

"The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle ."
  1. undefined
  2. undefined
  3. undefined
  4. undefined

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Solution


Let AB be a chord and angleAOB be the angle subtended by it at centre and angleAPB be the angle subtended at any point P on the remaining part of circle.
Now join PO and extend it to some point Q.
angleAPQ is external angle to triangle POA. angleAPQ= angleOPA + angle OAP.
Since OP and OA are radii of circle and hence equal, the triangle OAP is isoceles triangle. Therefore angle OPA = angle OAP.
angle APQ = 2×angleOPA. ....(I)
Similarly considering triangle OPB, angle BPQ = 2× angle OPB....(ii)
Adding (i) and (ii),
angle APQ + angle BPQ = 2× (angle OPA + angle OPB)
angle AOB = 2× angle APB ------ PROVED

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