The angle that is three times as large as its complement is

135^{o}

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{67.5}^{o}

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{50.5}^{o}

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45^{o}

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Solution

The correct option is B ${67.5}^{o}$
Let the angle be $x$
$∴ c o m p l e m e n t = (90 - x)$
$x = 3 (90 - x)$
$x = 270 - 3 x$
$4 x = 270$
$x = {67.5}^{o}$

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If the supplement of an angle is three times its complement, then angle is:

20^{o}

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