Question

The angle through which a cyclist has to bend himself to take a safe turn is given by :

• A. $ta{n}^{-1}\left(\frac{v^2}{Rg}\right)$
• B. $ta{n}^{-1}\left(\frac{2v^2}{Rg}\right)$
• C. $ta{n}^{-1}\left(\frac{Rg}{v^2}\right)$
• D. $ta{n}^{-1}\left(\frac{2Rg}{v^2}\right)$

Answer 1

The correct option is A $ta{n}^{-1}\left(\frac{v^2}{Rg}\right)$

The angle through which a cyclist has to bend himself, to prevent overturning himself is given by $ta{n}^{-1}\frac{v^2}{Rg}$.

Where $v$ is its linear velocity, $R$ is the radius of the turn and $g$ is the acceleration due to gravity.