Radial & Tangential Acceleration for Non Uniform Circular Motion
The angle tur...
Question
The angle turned by a body undergoing circular motion depends on time as θ=(2t2−θ0t3)rad, where θ0 is constant. Then the angular acceleration of the body at t=2s is
A
−12θ0rad/s2
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B
2−6θ0rad/s2
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C
4−12θ0rad/s2
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D
4−3θ0rad/s2
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Solution
The correct option is C4−12θ0rad/s2 Angular acceleration of the body is given as α=d2θdt2 We have, dθdt=d(2t2−θ0t3)dt=4t−3θ0t2 Similarly, d2θdt2=d(4t−3θ0t2)dt=4−6θ0t Thus, at t=2s we have α=4−6θ0×2=4−12θ0rad/s2