Question

The angle turned by a body undergoing circular motion depends on time as $\theta =\sqrt{2}{\theta }_0+3{\theta }_{1}t+{\theta }_2{t}^2$ Then the angular acceleration of the body is

• A. $\sqrt{{\theta }_1}$
• B. $\sqrt{3}{\theta }_2$
• C. $2{\theta }_1$
• D. $2{\theta }_2$

Answer 1

The correct option is D $2{\theta }_2$

$\begin{array}{c}\theta =\sqrt{2}{\theta }_o+3{\theta }_{1}t+{\theta }_2{t}^2\\ \omega =\frac{d\theta }{dt}=3{\theta }_1+2{\theta }_{2}t\\ \alpha =\frac{d\omega }{dt}=2{\theta }_2\\ \therefore optionDiscorrectanswer.\end{array}$