The angle which exceeds its complement by $20^{o}$ is:

45^{o}

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55^{o}

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70^{o}

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110^{o}

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Solution

The correct option is A $55^{o}$
Let the angle be $x$
$∴ c o m p l e m e n t = (90 - x)$
$x + (x + 20) = 90$
$2 x = 90 - 20$
$x = \frac{70}{2}$
$x = 35^{o}$
$∴$ other angle = $90 - 35 = 55^{o}$

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20^{o}

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