The angle which is one-fifth of its complement is:

15^{o}

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30^{o}

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45^{o}

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60^{o}

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Solution

The correct option is A $15^{o}$
We need to find out Angle which is $\frac{1}{5}$ of its complement is :
Let, the angle be $x$
$∴$ Its complement is $(90 - x)$
According to the question,
$x = \frac{1}{5} \times$ $(90 - x)$
$x = 18 - \frac{x}{5}$
Now, $x + \frac{x}{5} = 18$
$∴ \frac{5 x + x}{5} = 18$
or $\frac{6 x}{5} = 18$
or $6 x = 90$
$∴ x = 15^{o}$ .

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