The angle whose complement is one-third of its supplement will be

90^o

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135^o

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45^o

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180^o

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Solution

The correct option is C
45^o

Sum of complementary angles is 90^o,

Sum of supplementary angles is 180^o.

Let the required angle be x

According to the question 90^o –x =1/3(180^o – x).

Solving the equation for x to get x = 45^o.

Suggest Corrections

Similar questions

Find the angle whose;

i) Complement is one sixth of its supplement.

ii) Supplement is four times its complement.

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