The angles in a triangle are in the ratio 1:3:5. Find the measure of the largest angle.

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Solution

Let the angles be $x^{\circ}$ , $3 x^{\circ}$ and $5 x^{\circ}$

$x + 3 x + 5 x = 180^{\circ}$

$9 x = 180^{\circ}$

$x = \frac{180^{\circ}}{9} = 20^{\circ}$

Largest angle $= 5 x = 5 \times 20^{\circ} = 100^{\circ}$

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The angles in a triangle are in the ratio 1:3:5. Find the measure of the largest angle.

Let the angles be x∘, 3x∘ and 5x∘ x+3x+5x=180∘ 9x=180∘ x=180∘9=20∘ Largest angle =5x=5×20∘=100∘

Let the angles be $x^{\circ}$ , $3 x^{\circ}$ and $5 x^{\circ}$

$x + 3 x + 5 x = 180^{\circ}$

$9 x = 180^{\circ}$

$x = \frac{180^{\circ}}{9} = 20^{\circ}$

Largest angle $= 5 x = 5 \times 20^{\circ} = 100^{\circ}$