The angles in quadrilateral are $2 x, 3 x - 50, 4 x, 5 x - 10$ find $x$

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Solution

The angles of quadrilateral is $2 x, 3 x - 50, 4 x, 5 x - 10$
Their sum is $360^{\circ}$
$2 x + 3 x - 50 + 4 x + 5 x - 10 = 360 14 x - 60 = 360 14 x = 360 + 60 14 x = 420 x = \frac{420}{14} x = 30$

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The angles in quadrilateral are 2x,3x−50,4x,5x−10 find x

The angles of quadrilateral is 2x,3x−50,4x,5x−10Their sum is 360∘2x+3x−50+4x+5x−10=36014x−60=36014x=360+6014x=420x=42014x=30

The angles in quadrilateral are $2 x, 3 x - 50, 4 x, 5 x - 10$ find $x$

The angles of quadrilateral is $2 x, 3 x - 50, 4 x, 5 x - 10$
Their sum is $360^{\circ}$
$2 x + 3 x - 50 + 4 x + 5 x - 10 = 360 14 x - 60 = 360 14 x = 360 + 60 14 x = 420 x = \frac{420}{14} x = 30$