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Question

The angles of a quadrilateral are in A.P. whose common difference is 10. Find the angles.


Solution

Let the angles be (A),(A+d),(A+2d),(A+3d)
Here, d = 10
So, (A),(A+10),(A+20),(A+30) are the angles of a quadrilateral whose sum is 360.
(A),(A+10),(A+20),(A+30)
=3604A=36060A=3004=75
The angles are as follows:
75,(75+10),(75+20),(75+30),
i.e., 75,85,95,105


Mathematics
RD Sharma
Standard XI

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