Question

The angles of a triangle are $(2x{)}^0,(4x{)}^0,(6x{)}^0$.

What is the area of a right angled triangle whose base is (x + 3) cm and height is $\left(\frac{x}{5}\right)$ cm?

• A. $15c{m}^2$
• B. $27c{m}^2$
• C. $36c{m}^2$
• D. $18c{m}^2$

Answer 1

The correct option is B $27c{m}^2$

Sum of the angles of the triangle = ${180}^0$
So, 2x+4x+6x=180
12x=180, x=15
Area of the triangle =$\frac{1}{2}\times b\times h=\frac{1}{2}\times (x+3)\left(\frac{x}{5}\right)$
$=\frac{1}{2}\times 18\times 3=9\times 3=27c{m}^2$