Question

The angles of a triangle are in A.P. and the greatest angle is double the least. Find all the angles in circular measure.

• A. $40,60,80$
• B. $40,60,50$
• C. $40,70,80$
• D. $20,60,80$

Answer 1

Answer: (A)

$40,60,80$

Let the angles be $a-d,a,a+d.$

& $2(a-d)=a+d,2a-2d=a+d,a=3d⟶\left(i\right)$

$a-d+a+a+d=180°,3a=180°,a=60°.d=20°.$

$a-d,a,a+d=40,60,80$.