The angles of a triangle are in the ratio $1 : 3 : 5$ then the greatest angle is

\frac{5 π}{9}

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\frac{2 π}{9}

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\frac{7 π}{9}

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\frac{11 π}{9}

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Solution

The correct option is A $\frac{5 π}{9}$
Let one angle of triangle $= x$
Let $I I n d$ angle of triangle $= 3 x$
Let $I I I r d$ angle of triangle $= 5 x$
Sum of the angles of triangle $= 180^{o}$
$x + 3 x + 5 x = π$
$9 x = \frac{π}{9}$
$I I n d$ angle $= \frac{3 π}{9} = \frac{π}{3}$
$I I I r d$ angle $= \frac{5 π}{9}$
$∴$ The greatest angle is $\frac{5 π}{9}$

Suggest Corrections

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