Suppose ∆ABC be such that ∠A : ∠B : ∠C = 2 : 3 : 4.
Let ∠A = 2k, ∠B = 3k and ∠C = 4k, where k is some constant.
In ∆ABC,
∠A + ∠B + ∠C = 180º (Angle sum property)
⇒ 2k + 3k + 4k = 180º
⇒ 9k = 180º
⇒ k = 20º
∴ Measure of the largest angle = 4k = 4 × 20º = 80º
Hence, the correct answer is option (c).