Question

The angles of a triangle are in the ratio $3:5:10$. Find the measure of each angle of the triangle.

Answer 1

Let the three angles of a triangle be $3x,5x,10x$
$\Rightarrow 3x+5x+10x={180}^{\circ }$
$\Rightarrow 18x={180}^{\circ }$
$\Rightarrow x=\frac{180}{18}$
$\therefore x={10}^{\circ }$
Thus, the angles are $3\left(10\right)={30}^{\circ },5\left(10\right)={50}^{\circ },10\left(10\right)={100}^{\circ }$