Question

The angles of a triangle are ${(x-40)}^{},{(x-20)}^{}$ and ${(1/2x-10)}^{}$. Find the value of x.

Answer 1

The sum of measures of angles of a triangles is 180 degrees

$\therefore (x-40)+(x-20)+(x/2-10)={180}^o$

$\therefore 5x/2-{70}^o={180}^o$

$\therefore 5x/2={250}^o$

$\therefore 5x={500}^o$

$\therefore x={100}^o$