Question

The angles of depression of the top of an 8 m tall building from the top of a multi-storeyed building is ${45}^{\circ }$. Find the height of the multi-storeyed building if the distance between the two buildings is $10m$

Answer 1

The angle of depression is ${45}^{\circ }$

The distance between the buildings is $10m$

The height of multi-storeyed building above the building is $\tan 45=\frac{Height}{Distance}1=\frac{Height}{10}Height=10m$

So the total height is $10+8=18m$