Question

The angles of triangle are ${45}^{\circ },{60}^{\circ }$ find the third angle .

Answer 1

Let the triangle be $\Delta ABC$

The sum of angles in triangle is ${180}^{\circ }$

${45}^{\circ }+{60}^{\circ }+\angle C={180}^{\circ }\angle C=180-45-60\angle C={75}^{\circ }$