Question 8
The angles $x - 10^{\circ} a n d 190^{\circ} - x$ are
(a) Interior angles on the same side fo the transversal
(b) making a linear pair
(c) complementary
(d) supplementary

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Solution

Sum of the given angles $= (x - 10^{\circ}) + (190^{\circ} - x) = x - 10^{\circ} + 190^{\circ} - x = (x - x) + (190^{\circ} - 10^{\circ}) = 0 + 180^{\circ} = 180^{\circ}$
Since, the sum of given angles is $180^{\circ}$ . Hence, they are supplementary.

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Similar questions

Q. Question 8
The angles

x - 10^{\circ} a n d 190^{\circ} - x

are
(a) Interior angles on the same side fo the transversal
(b) making a linear pair
(c) complementary
(d) supplementary

The angles 'x' and ' $90^{\circ}$ - x' are :

Q. Question 7
The angles x and

90^{\circ} - x

are
(a) supplementary
(b) complementary
(c) vertically opposite
(d) making a linear pair

In the given diagram, $∠$ XOB and $∠$ YO'P are called ________.

Question 96

If a transversal intersects two parallel lines and the difference of two interior angles on the same side fo a transversal is $20^{\circ}$ , find the angles.

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Supplementary Angles

Standard VII Mathematics

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Question 8 The anglesx−10∘and190∘−x are (a) Interior angles on the same side fo the transversal (b) making a linear pair (c) complementary (d) supplementary

Sum of the given angles=(x−10∘)+(190∘−x)=x−10∘+190∘−x=(x−x)+(190∘−10∘)=0+180∘=180∘ Since, the sum of given angles is 180∘. Hence, they are supplementary.

Question 8
The angles $x - 10^{\circ} a n d 190^{\circ} - x$ are
(a) Interior angles on the same side fo the transversal
(b) making a linear pair
(c) complementary
(d) supplementary

Sum of the given angles $= (x - 10^{\circ}) + (190^{\circ} - x) = x - 10^{\circ} + 190^{\circ} - x = (x - x) + (190^{\circ} - 10^{\circ}) = 0 + 180^{\circ} = 180^{\circ}$
Since, the sum of given angles is $180^{\circ}$ . Hence, they are supplementary.