Question 8
The angles $x - 10^{\circ} a n d 190^{\circ} - x$ are
(a) Interior angles on the same side fo the transversal
(b) making a linear pair
(c) complementary
(d) supplementary

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Solution

Sum of the given angles $= (x - 10^{\circ}) + (190^{\circ} - x) = x - 10^{\circ} + 190^{\circ} - x = (x - x) + (190^{\circ} - 10^{\circ}) = 0 + 180^{\circ} = 180^{\circ}$
Since, the sum of given angles is $180^{\circ}$ . Hence, they are supplementary.

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Question 8 The anglesx−10∘and190∘−x are (a) Interior angles on the same side fo the transversal (b) making a linear pair (c) complementary (d) supplementary

Sum of the given angles=(x−10∘)+(190∘−x)=x−10∘+190∘−x=(x−x)+(190∘−10∘)=0+180∘=180∘ Since, the sum of given angles is 180∘. Hence, they are supplementary.

Question 8
The angles $x - 10^{\circ} a n d 190^{\circ} - x$ are
(a) Interior angles on the same side fo the transversal
(b) making a linear pair
(c) complementary
(d) supplementary

Sum of the given angles $= (x - 10^{\circ}) + (190^{\circ} - x) = x - 10^{\circ} + 190^{\circ} - x = (x - x) + (190^{\circ} - 10^{\circ}) = 0 + 180^{\circ} = 180^{\circ}$
Since, the sum of given angles is $180^{\circ}$ . Hence, they are supplementary.