The angular displacement of a particle is given by θ=ω0t+12αt2, where ω0 and α are constant and ω0=1rad/sec,α=1.5rad/sec2. The angular velocity (in rad/s) at time, t=2sec will be
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D4 We have θ=ω0t+12αt2, we know that angular velocity is the rate of change of angular position of a rotating body.
⇒dθdt=ω0+αt This is angular velocity at time t. Now angular velocity at t=2sec will be ω=(dθdt)t=2sec=ω0+2α