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Angular Velocity

The angular d...

Question

The angular displacement of a particle is given by theta =t^3+t^2+t+1 then it's angular velocity at t=2sec is given by__________rad per sec

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Solution

Angular velocity of a body=d(theta)/dt
that is first derivative of displacement gives its velocity
so
angulat velocity=3t^2+2t+1
(first derivative)
so at t=2 s
angular velocity=34+22+1
=12+4+1=17 rad/sec

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Similar questions

θ = t^{3} + t^{2} + t + 1

t = 2

r a d s^{- 1}

θ = ω_{0} t + \frac{1}{2} α t^{2}

ω_{0}

α

ω_{0} = 1 rad/sec, α = 1.5 {rad/sec}^{2}

(

rad/s)

t = 2 sec

θ = ω_{0} t + \frac{1}{2} α t^{2}

ω_{0}

α

ω_{0} = 1 rad/sec, α = 1.5 {rad/sec}^{2}

(

rad/s)

t = 2 sec

θ = ω_{0} t + \frac{1}{2} α t^{2}

ω_{0}

α

ω_{0} = 1 r a d / s e c, α = 1.5 r a d / s e c^{2}

t = 2 s e c

r a d / s e c

θ = 2 t^{2} + 2 t - 3

t = 2 sec

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