Question

The angular displacement of a particle is given by $\theta =t^3+t^2+t+1$ then, its angular velocity at $t=2$ sec is _____ $rad{s}^{-1}$ :

• A. $27$
• B. $17$
• C. $15$
• D. $6$

Answer 1

The correct option is B $17$

$\omega =\frac{d\theta }{dt}$$=3t^2+2t+1$
at, $t=2sec,$
$\omega =12+4+1$
$=17rad/s$