Question

The angular displacement of a particle is given by $\theta =t^3+t^2+t+1$ then, its angular velocity at $t=2sec$ is _________rad $s^{-1}$

• A. 27
• B. 17
• C. 15
• D. 16

Answer 1

Answer: (B)

17

Given that angular displacement of the particle is given by $\theta =t^3+t^2+t+1$

So angular velocity = $\omega =\frac{d\theta }{dt}=3t^2+2t+1$

= at t = 2 secs

angular velocity =$\omega =17rad{s}^{-1}$