Question

The angular frequency of a simple pendulum is $\omega$ rad/sec. Now, if the length is made one-fourth of the original length, the angular frequency becomes

• A. $\omega /2$
• B. $2\omega$
• C. $4\omega$
• D. $\omega$

Answer 1

The correct option is B $2\omega$

The angular frequency of simple pendulum is
$\omega =\sqrt{\frac{g}{l}}$
The new angular frequency when length is reduced to one fourth is
${\omega }_{new}=\sqrt{\frac{g}{\frac{l}{4}}}=\sqrt{\frac{4g}{l}}=2\omega$
Option B is thus correct.