The angular frequency of motion whose equation is 4d2y-dt2-9y-0 is y - displacement and t - time

A particle executes simple harmonic motion about the point X =0 . At time t =0 it has displacement cm and zero velocity. If the frequency of motion is $0.25 s e c^{- 2}$ , find
(a) the time period,
(b) angular frequency,
(c) the amplitude,
(d) maximum speed,
(e) the displacement at t =3 sec and
(f) the velocity at t =3 sec.

Q. A wave is travelling along positive

x -

direction with speed

4 m/s

. Further, equation of the wave pulse at

t = 0

y (x, 0) = \frac{5}{4 + (3 x + 6)^{2}}

. The equation of the same pulse after

t s

will be

Q. If

y = 1 + t^{4}

and

x = 3 t^{3} + t

then what is

\frac{d y}{d x}

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The angular frequency of motion whose equation is 4d2ydt2+9y=0 is (y = displacement and t = time)

The correct option is C 32The angular frequency of motion whose equation is4d2ydt2+9y=0d2ydt2+9y4=0ω2=94ω=32

The angular frequency of motion whose equation is $4 \frac{d^{2} y}{d t^{2}} + 9 y = 0$ is (y = displacement and t = time)

The correct option is C $\frac{3}{2}$
The angular frequency of motion whose equation is $4 \frac{d^{2} y}{d t^{2}} + 9 y = 0$
$\frac{d^{2} y}{d t^{2}} + \frac{9 y}{4} = 0$

$ω^{2} = \frac{9}{4}$

$ω = \frac{3}{2}$