Question

The angular frequency of the damped oscillator is given by,
$\omega =\sqrt{(\frac{k}{m}-\frac{r^2}{4m^2})}$ where k is the spring constant, m is the mass of the oscillator and r is the damping constant. If the ratio $\frac{r^2}{mk}$ is 80%, the change in time period compared to the undamped oscillator is approximately as follows :

• A. increases by 8%
• B. decreases by 8%
• C. increases by 1%
• D. decreases by 1%

Answer 1

Answer: (A)

increases by 8%

The change in time period compared to the undamped oscillator increases by 8%.