The angular momentum of an electron in a hydrogen atom is proportional to(where n is principle quantum number).

n

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n^{2}

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n^{3}

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\sqrt{n}

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Solution

The correct option is A $n$
According to Bohr's model
The angular momentum of orbiting electron =L =mvr = $\frac{n h}{2 π}$
Therefore,
$L \propto n$

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