Question

The angular momentum of an electron in a s orbital is given as :

• A. 0
• B. h/2$\pi$
• C. 1
• D. none

Answer 1

Answer: (A)

0

Angular momentum in an orbital $=\frac{h}{2\pi }\sqrt{\ell (\ell +1)}$

$\ell =0$ for $s$ orbital, hence orbital angular momentum $=0$

$\ell =1$ for $p$ orbital

$Angularmomentum=\frac{h}{2\pi }\sqrt{(1+1)\times 1}=\frac{h}{\sqrt{2\pi }}$