The angular momentum of electron in 4th orbit of hydrogen atom is

\frac{4 h}{π}

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\frac{2 h}{π}

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\frac{n h}{2 π}

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\frac{h}{4 π}

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Solution

The correct option is C $\frac{n h}{2 π}$
The angular momentum of electron in $4 t h$ orbit of hydrogen atom is $\frac{n h}{2 π}$
Hence, Option $C$ is correct.

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