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Bohrs Derivations

The angular m...

Question

The angular momentum of electron in ‘d‘ orbital is equal to :

A

$0 ℏ$

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B

$\sqrt{6} ℏ$

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C

$\sqrt{2} ℏ$

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D

$2 \sqrt{3} ℏ$

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Solution

The correct option is B
$\sqrt{6} ℏ$

Angular momentum of electron in 'd' orbital $\sqrt{l (l + 1)} ℏ = \sqrt{2 (2 + 1)} ℏ = \sqrt{6} ℏ$

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