Question

The angular momentum of the electron in the second orbit of hydrogen atom is L. The angular momentum in the third orbit is

• A. L
• B. 3L
• C. (3/2)L
• D. (2/3)L

Answer 1

The correct option is C

(3/2)L

Angular momentum $=\frac{nh}{2\pi }$ ; Thus, for an electron in the $2^{nd}orbit,L=\frac{2h}{2\pi }=\frac{h}{\pi }$

For an electron in the $3^{rd}orbit.L^{\prime }\frac{3h}{2\pi }.L^{\prime }=\frac{3}{2}L$