The angular position of a particle revolving around a circular path given by -t2-3t-4radian-Find the accelaration of the point at t-2sec -Given radious-1 1-2m-s2 2-5m-s2- 3-1m-s2 4-5m-s

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Angular Magnification in Simple Microscope

the angular p...

Question

the angular position of a particle revolving around a circular path given by θ=t2-3t+4radian.Find the accelaration of the point at t=2sec .Given radious=1 1)2m/s2 2)\sqrt{5m/s2} 3)1m/s2 4)5m/s

Open in App

Solution

Suggest Corrections

Similar questions

Q. The angular displacement of a particle is given by

θ = t^{3} + t^{2} + t + 1

then, its angular velocity at

t = 2 s e c

is _________rad

s^{- 1}

Q. A particle is revolving in a circular path of radius

200 m

at a speed of

20 m / s

. Its speed is increasing at the rate of

\sqrt{5} m / s^{2}

. Its acceleration is

Q. The angular position of a point on the rim of a rotating wheel is given by

θ = 4 t - 3 t^{2} + t^{3}

, where

θ

is in radians and

t

is in seconds. What is the instantaneous angular acceleration at

t = 2 sec

Angular position of a particle performing circular motion is given by $θ = (t^{2} - 2 t) r a d$ . Consider the ads circular track $2 m$ Angular distance of particle at $t = 3 s$

Q. A particle is revolving in a circular path having radius

‘ r^{'} = 1 m

at a speed of

2 m / s

. It is increasing its speed at the rate of

3 m / s^{2}

. The magnitude of total acceleration of the particle at that instant is

Join BYJU'S Learning Program