Question

The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16sec.? find.
(i) Angular acceleration
(ii) Assuming acceleration to be uniform how many rotations does the engine make this bike?
(iii) State law of conservation of linear momentum?

Answer 1

${\omega }_1=1200rpm$

$=\frac{1200\times 2\pi }{60}=40\pi rad.s^{-1}$

${\omega }_2=\frac{3120\times 2\pi }{60}=10\pi rad.s^{-1}$

$t=16\sec$

$\left(1\right)$ Angular acceleration

$a=\frac{({\omega }_2-{\omega }_1)}{16}=\frac{64\pi }{16}$

$=4\pi rad.s^{-1}$

$\left(2\right)$ Angle, $\theta$ $=40\pi 16+\frac{1}{2}\left(4\pi \right)\times 256$

$=1152rad.$

$\left(3\right)$ When there is no any external force applied on a system of partials then, momentum of system of particles will be consecrate or you can say that if external force is zero, then momentum of system of particles is initially $=$ Momentum of system of particles is finally.