Question

The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is

[CBSE PMT 1991]

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Kinetic energy T = $\frac{1}{2}m{\omega }^2(a^2-x^2)$
and potential energy , V = $\frac{1}{2}m{\omega }^2{x}^2$

$\therefore \frac{T}{V}=\frac{a^2-x^2}{x^2}$