The angular velocity of the earth with which it has to rotate so that acceleration due to gravity on 60∘ latitude becomes zero is (Radius of earth = 6400 At the poles g = 10ms−2)
2.5×10−3 rad/sec
Effective acceleration due to gravity due to rotation of earth g′=g−ω2 R cos2 λ
⇒0=g−w2 R cos2 60∘⇒w=√4gR=2√gR=2800radsec[As g′=0 and λ=60∘]⇒ω=1400=2.5×10−3radsec