wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The angular width of the central maximum in a single slit diffraction pattern is 60o. The width of the slit is 1 μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young's fringes can be observed on a screen placed at a distance 50cm from the slits. If the observed fringe width is 1cm, what is slit separation distance? (i.e., distance between the centres of each slit.)

A
75μm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100μm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25μm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
50μm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 25μm
Angular width of the central maxima θc=60o
Half angle θ=60o2=30o
Given : b=106 m
Using sinθ=λb
Or sin30o=λ106
λ=0.5×106 m
Given : D=50 cm=0.5 m
Fringe width β=1 cm=0.01 m
Using β=λ Dd
0.01=0.5×106×0.50.01=25μm

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Playing with Glass Slabs
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon