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Question

The anhydride of Nitrous Acid(HNO2) is


A

N2O3

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B

N2O

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C

NO

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D

N2O4

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Solution

The correct option is A

N2O3


The oxidation number of nitrogen in Nitrous Acid(HNO2) is ‘+3’.

The oxidation number for nitrogen atom in anhydride of Nitrous Acid(HNO2) must be ‘+3’.

Explanation of correct option-

Let the oxidation number of ‘N’ in N2O3 is ‘p’.

Then

2(p)+3(-2)=02p-6=0p=+3

The oxidation number of ‘N’ in N2O3 is ‘+3’.

Explanation of incorrect options-

Let the oxidation number of N in N2O is ‘q’.

Then

2(q)+(-2)=02q-2=02q=2q=+1

The oxidation number of N in N2O is ‘+1’.

Let the oxidation number of N in NO is ‘r’.

Then

r+(-2)=0r-2=0r=+2

The oxidation number of N in NO is ‘+2’.

Let the oxidation number of N in N2O4 is ‘s’.

Then

2(s)+4(-2)=02s-8=02s=8s=+4

The oxidation number of N in N2O4 is ‘+4’

Hence, Option(A) is correct.


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