The anhydride of orthophosphoric acid is :

P_{4} O_{6}

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P_{2} O_{4}

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P_{4} O_{10}

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H_{2} P_{2} O_{6}

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Solution

The correct option is C $P_{4} O_{10}$
$2 H_{3} P O_{4} - 3 H_{2} O - --- \to P_{2} O_{s}$
$P_{2} O_{s}$ exist as $P_{4} O_{10}$

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P O_{4}^{3 -}, P_{4} O_{10}

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P_{4} O_{10}

P_{4} O_{6}

P_{4} O_{10}

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