The anion whose sodium salt gives white precipitate only on boiling when treated with $M g C l_{2}$ is :

S O_{4}^{2 -}

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H C O_{3}^{-}

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C O_{3}^{2 -}

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N O_{3}^{-}

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Solution

The correct option is B $H C O_{3}^{-}$
A sodium salt of an unknown anion when treated with $M g C l_{2}$ gives white precipitate only on boiling. The anion is $H C O_{3}^{-}$ .
$M g C 1_{2} + 2 N a H C O 3 \to M g (H C O_{3})_{2} soluble + 2 N a C l$ $Δ - \to M g C O_{3} white ↓ + H_{2} O + C O_{2}$

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