The annual precipitation data of a city is normally distributed with mean and standard deviation a 1000 mm and 200 mm, respectively. The probability that the annual precipitation will be more than 1200 mm is
A
<50%
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B
50%
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C
75%
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D
100%
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Solution
The correct option is A <50% μ=1000,σ=200,z=x−μσ
& x = {Annual precipitation data}
z=1200−1000200=1
Required Probability is
P(x > 1200)
= P(Z > 1) =0.5−P(0<Z<1) <0.5