The anodic half-cell of lead-acid battery is recharged using electricity of 0.05 Faraday. The amount of PbSO4 electrolysed in g during the process is:(molar mass of PbSO4=303 g mol−1)
A
22.8
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B
15.2
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C
7.6
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D
11.4
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Solution
The correct option is B 15.2 (Anode)PbSO4(s)+2OH−→PbO2+H2SO4+2e−0.05/2mole0.05F(Cathode)PbSO4+2e−+2H+→Pb(s)+H2SO40.05/2mole0.05FnT(PbSO4)=0.05×303=15.2g