Question

The answer to each of the following question is a single digit integer, ranging from 0 to 9.

Number of moles of $O_2$ formed by 136 g of $H_2{O}_2$, on complete decomposition will be:

Answer 1

$\begin{array}{c}2H_2{O}_2\to 2H_{2}O+O_2\\ 2molof{H}_2{O}_2\to 1molof{O}_2\\ 2\times 34gm{H}_2{O}_2\to 32gm\end{array}$

$\frac{136}{68}=2$mol of $H_2{O}_2$ gives

$\Rightarrow 1mol$ of $O_2$