The answer to each of the following questions is a single digit integer, ranging from 0 to 9.
Two moles of sodium phosphate completely reacts with calcium chloride to form calcium phosphate $C a_{3} (P O_{4})_{2}$ . How many moles of calcium phosphate will be fanned ?

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Solution

A balanced chemical equation is:
$C a C l_{2} + 2 N a_{3} P O_{4} \to 6 N a C l + C a_{3} (P O_{4})_{2}$
Total moles of $C a C l_{2} =$ 89.3g/110.98g/mol = 0.805
The ratio between $C a C l_{2}$ and $C a_{3} (P O_{4})_{2}$ is $3 : 1$
moles of $C a_{3} (P O_{4})_{2} = 0.805 / 3 = 0.268$
mass of $C a_{3} (P O_{4})_{2} = 0.268 m o l \times 310.17 g / m o l = 83.1 g$

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