Question

The answer to this question is a single digit integer, ranging from 0 to 9.

The pH of an aqueous solution of 1 M solution of a weak monoprotic acid which is 1% ionised is.

Answer 1

$\left[H^{+}\right]=C\alpha$
Where C is concentration and $\alpha$ is degree of dissociation.
$H^{+}=0.1\times 0.01$
$H^{+}={10}^{-3}$
$pH=-log\left[H^{+}\right]$
$pH=-log\left[{10}^{-3}\right]$
$pH=3$.
So answer is 3.